Motion Physics Examples Solved

Task:

motion-physics-examples-solved

Consider a simple model for a rocket launched from the surface of the Earth. A better expression for a rocket’s position measured from the center of the Earth is given by:

01

where RE is the radius of the Earth (6.38 ✕ 106m) and g is the constant acceleration
of an object in free fall near the Earth’s surface (9.81 m/s2).

(a) Determine expressions for velocity and acceleration of the rocket
(b) When will the rocket be at y = 4R_{E} ?
(c) What are the velocity and the acceleration when y = 4R_{E} ?

Solution:

(a) Velocity of the rocket is

02

Acceleration of the rocket is

03

(b) When y = 4R_{E}

04

(c) The velocity of the rocket when y = 4R_{E} or \frac{7}{3}\sqrt{\frac{2R_{E}}{g}} is

v_y = \frac{R_E\sqrt{2g}}{(R_E^{3/2} + 3\sqrt{\frac{g}{2}}R_E * \frac{7}{3} \sqrt{\frac{2R_{E}}{g}})^{1/3}} = \frac{R_E\sqrt{2g}}{(8R_{E}^{3/2})^{1/3}} = \sqrt{\frac{gR_{E}}{2}} (m/s)

The acceleration of the rocket when y = 4R_{E} or t = \frac{7}{3} \sqrt{\frac{2R_{E}}{g}} is

05

Answers:

(a) 06

(b) 07

(c) 08

This paper is a sample created by our academic experts. Read our blog to find out more motion physics examples, assignments on other subjects and general studying tips. We remind you that you are not allowed to use the solution posted here without proper references, since it will be a violation of the author’s rights. Place your order to get your own motion physics examples to study from! Our skilled experts can do any type of assignment for you on any subject, not just physics or mathematics. Visit our website to learn more and, of course, we are waiting for your order.

You can also be interested in other solved problems in physics explained in details.

Leave a Reply

Your email address will not be published. Required fields are marked *

Customer testimonials

Submit your instructions to the experts without charge.